Optimal. Leaf size=102 \[ -a^3 x+\frac {3}{2} a b^2 x-\frac {3 a^2 b \tanh ^{-1}(\cos (c+d x))}{d}+\frac {3 a^2 b \cos (c+d x)}{d}-\frac {b^3 \cos ^3(c+d x)}{3 d}-\frac {a^3 \cot (c+d x)}{d}+\frac {3 a b^2 \cos (c+d x) \sin (c+d x)}{2 d} \]
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Rubi [A]
time = 0.08, antiderivative size = 102, normalized size of antiderivative = 1.00, number of steps
used = 11, number of rules used = 9, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.429, Rules used = {2801, 2715, 8,
2672, 327, 212, 3554, 2645, 30} \begin {gather*} -\frac {a^3 \cot (c+d x)}{d}+a^3 (-x)+\frac {3 a^2 b \cos (c+d x)}{d}-\frac {3 a^2 b \tanh ^{-1}(\cos (c+d x))}{d}+\frac {3 a b^2 \sin (c+d x) \cos (c+d x)}{2 d}+\frac {3}{2} a b^2 x-\frac {b^3 \cos ^3(c+d x)}{3 d} \end {gather*}
Antiderivative was successfully verified.
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Rule 8
Rule 30
Rule 212
Rule 327
Rule 2645
Rule 2672
Rule 2715
Rule 2801
Rule 3554
Rubi steps
\begin {align*} \int \cot ^2(c+d x) (a+b \sin (c+d x))^3 \, dx &=\int \left (3 a b^2 \cos ^2(c+d x)+3 a^2 b \cos (c+d x) \cot (c+d x)+a^3 \cot ^2(c+d x)+b^3 \cos ^2(c+d x) \sin (c+d x)\right ) \, dx\\ &=a^3 \int \cot ^2(c+d x) \, dx+\left (3 a^2 b\right ) \int \cos (c+d x) \cot (c+d x) \, dx+\left (3 a b^2\right ) \int \cos ^2(c+d x) \, dx+b^3 \int \cos ^2(c+d x) \sin (c+d x) \, dx\\ &=-\frac {a^3 \cot (c+d x)}{d}+\frac {3 a b^2 \cos (c+d x) \sin (c+d x)}{2 d}-a^3 \int 1 \, dx+\frac {1}{2} \left (3 a b^2\right ) \int 1 \, dx-\frac {\left (3 a^2 b\right ) \text {Subst}\left (\int \frac {x^2}{1-x^2} \, dx,x,\cos (c+d x)\right )}{d}-\frac {b^3 \text {Subst}\left (\int x^2 \, dx,x,\cos (c+d x)\right )}{d}\\ &=-a^3 x+\frac {3}{2} a b^2 x+\frac {3 a^2 b \cos (c+d x)}{d}-\frac {b^3 \cos ^3(c+d x)}{3 d}-\frac {a^3 \cot (c+d x)}{d}+\frac {3 a b^2 \cos (c+d x) \sin (c+d x)}{2 d}-\frac {\left (3 a^2 b\right ) \text {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\cos (c+d x)\right )}{d}\\ &=-a^3 x+\frac {3}{2} a b^2 x-\frac {3 a^2 b \tanh ^{-1}(\cos (c+d x))}{d}+\frac {3 a^2 b \cos (c+d x)}{d}-\frac {b^3 \cos ^3(c+d x)}{3 d}-\frac {a^3 \cot (c+d x)}{d}+\frac {3 a b^2 \cos (c+d x) \sin (c+d x)}{2 d}\\ \end {align*}
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Mathematica [A]
time = 0.87, size = 143, normalized size = 1.40 \begin {gather*} \frac {\left (36 a^2 b-3 b^3\right ) \cos (c+d x)-b^3 \cos (3 (c+d x))-6 a^3 \cot \left (\frac {1}{2} (c+d x)\right )+9 a b^2 \sin (2 (c+d x))+6 a \left (-2 a^2 c+3 b^2 c-2 a^2 d x+3 b^2 d x-6 a b \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )+6 a b \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right )+a^2 \tan \left (\frac {1}{2} (c+d x)\right )\right )}{12 d} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.15, size = 96, normalized size = 0.94
method | result | size |
derivativedivides | \(\frac {a^{3} \left (-\cot \left (d x +c \right )-d x -c \right )+3 a^{2} b \left (\cos \left (d x +c \right )+\ln \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right )\right )+3 a \,b^{2} \left (\frac {\cos \left (d x +c \right ) \sin \left (d x +c \right )}{2}+\frac {d x}{2}+\frac {c}{2}\right )-\frac {b^{3} \left (\cos ^{3}\left (d x +c \right )\right )}{3}}{d}\) | \(96\) |
default | \(\frac {a^{3} \left (-\cot \left (d x +c \right )-d x -c \right )+3 a^{2} b \left (\cos \left (d x +c \right )+\ln \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right )\right )+3 a \,b^{2} \left (\frac {\cos \left (d x +c \right ) \sin \left (d x +c \right )}{2}+\frac {d x}{2}+\frac {c}{2}\right )-\frac {b^{3} \left (\cos ^{3}\left (d x +c \right )\right )}{3}}{d}\) | \(96\) |
risch | \(-a^{3} x +\frac {3 a \,b^{2} x}{2}-\frac {3 i a \,b^{2} {\mathrm e}^{2 i \left (d x +c \right )}}{8 d}+\frac {3 b \,{\mathrm e}^{i \left (d x +c \right )} a^{2}}{2 d}-\frac {b^{3} {\mathrm e}^{i \left (d x +c \right )}}{8 d}+\frac {3 b \,{\mathrm e}^{-i \left (d x +c \right )} a^{2}}{2 d}-\frac {b^{3} {\mathrm e}^{-i \left (d x +c \right )}}{8 d}+\frac {3 i a \,b^{2} {\mathrm e}^{-2 i \left (d x +c \right )}}{8 d}-\frac {2 i a^{3}}{d \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )}-\frac {3 a^{2} b \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{d}+\frac {3 a^{2} b \ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{d}-\frac {b^{3} \cos \left (3 d x +3 c \right )}{12 d}\) | \(204\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.62, size = 95, normalized size = 0.93 \begin {gather*} -\frac {4 \, b^{3} \cos \left (d x + c\right )^{3} + 12 \, {\left (d x + c + \frac {1}{\tan \left (d x + c\right )}\right )} a^{3} - 9 \, {\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} a b^{2} - 18 \, a^{2} b {\left (2 \, \cos \left (d x + c\right ) - \log \left (\cos \left (d x + c\right ) + 1\right ) + \log \left (\cos \left (d x + c\right ) - 1\right )\right )}}{12 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.40, size = 143, normalized size = 1.40 \begin {gather*} -\frac {9 \, a b^{2} \cos \left (d x + c\right )^{3} + 9 \, a^{2} b \log \left (\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) \sin \left (d x + c\right ) - 9 \, a^{2} b \log \left (-\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) \sin \left (d x + c\right ) + 3 \, {\left (2 \, a^{3} - 3 \, a b^{2}\right )} \cos \left (d x + c\right ) + {\left (2 \, b^{3} \cos \left (d x + c\right )^{3} - 18 \, a^{2} b \cos \left (d x + c\right ) + 3 \, {\left (2 \, a^{3} - 3 \, a b^{2}\right )} d x\right )} \sin \left (d x + c\right )}{6 \, d \sin \left (d x + c\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \left (a + b \sin {\left (c + d x \right )}\right )^{3} \cot ^{2}{\left (c + d x \right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 199 vs.
\(2 (96) = 192\).
time = 12.66, size = 199, normalized size = 1.95 \begin {gather*} \frac {18 \, a^{2} b \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) \right |}\right ) + 3 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 3 \, {\left (2 \, a^{3} - 3 \, a b^{2}\right )} {\left (d x + c\right )} - \frac {3 \, {\left (6 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + a^{3}\right )}}{\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )} - \frac {2 \, {\left (9 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 18 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 6 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 36 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 9 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 18 \, a^{2} b + 2 \, b^{3}\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}^{3}}}{6 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 6.86, size = 289, normalized size = 2.83 \begin {gather*} \frac {a^3\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{2\,d}-\frac {\ln \left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )-\mathrm {i}\right )\,\left (\frac {a\,b^2\,3{}\mathrm {i}}{2}-a^3\,1{}\mathrm {i}\right )}{d}+\frac {\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (12\,a^2\,b-\frac {4\,b^3}{3}\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6\,\left (a^3+6\,a\,b^2\right )-3\,a^3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\left (6\,a\,b^2-3\,a^3\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5\,\left (12\,a^2\,b-4\,b^3\right )-a^3+24\,a^2\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{d\,\left (2\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7+6\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5+6\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3+2\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}+\frac {3\,a^2\,b\,\ln \left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{d}-\frac {a\,\ln \left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )+1{}\mathrm {i}\right )\,\left (2\,a^2-3\,b^2\right )\,1{}\mathrm {i}}{2\,d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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